DE (Double Exponential) Integration over (−∞, ∞)
Numerically integrate ∫f(x)dx over the whole real line with the double exponential (DE) transform. Just enter f(x) and the number of nodes.
Input
Numerically evaluate the definite integral ∫f(x)dx over (−∞, ∞) using the DE (double exponential) formula. Enter the integrand and the number of nodes.
e.g. exp(-x^2), 1/(1+x^2), exp(-x^2)*cos(x). Supports x, pi, e and sin/cos/exp/log/sqrt, etc.
Total samples are 2N+1 (5 to 5000).
Result
Integral ∫f(x)dx
1.7724538509
Total nodes
401
Half nodes N
200
Step h
0.02
Computation details
| Integrand | exp(-x^2) |
| Total nodes | 401 |
| Step h | 0.02 |
| Effective nodes | 165 |
| Max reach |x| | 24.605 |
How it works
- Integrates ∫f(x)dx over (−∞, ∞) by applying the double exponential (DE) change of variables x = sinh((π/2)·sinh t), mapping the infinite interval to a finite one summed with the equally spaced trapezoidal rule.
- The Jacobian dx/dt = (π/2)·cosh(t)·cosh((π/2)·sinh t) is used as the quadrature weight, sampling at grid points t_k = k·h for k = −N…N.
- This transform makes the integrand decay doubly exponentially toward the endpoints, so it converges rapidly with relatively few nodes even on an unbounded domain.
- The integrand is parsed by a custom recursive descent parser (no eval). It supports + − * / ^, parentheses, unary minus, implicit multiplication, the variable x, the constants pi and e, and the functions sin, cos, tan, asin, acos, atan, sinh, cosh, tanh, exp, log, ln, log10, sqrt, cbrt and abs.
- Computation uses double precision floating point, so accuracy is highest when the integrand decays quickly at both tails. Slowly decaying or strongly oscillatory integrands may retain some error.
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DE (Double Exponential) Integration over (−∞, ∞)