Parabolic Segment Area (Archimedes Theorem)
Find the area of a parabolic segment bounded by a chord and a parabola from the chord width (base) and height. The area equals two thirds of base times height, with ratio and arc length too.
Input
Calculate the area of a parabolic segment bounded by a parabola and its chord from the chord width (base) and the height.
Result
Segment area
32
Enclosing triangle area
24
Segment to rectangle ratio
2 : 3
Parabolic arc length
15.073706
By the Archimedes theorem the segment area equals (2/3) times base times height.
Lengths use the same unit as the input, and area is in that unit squared.
How it works
- A region bounded by a parabola and a chord across it is called a parabolic segment.
- By the quadrature of the parabola due to Archimedes, the segment area equals four thirds of the triangle that shares the same base and height.
- With chord width as the base b and the distance from the vertex to the chord as the height h, the segment area is (2/3) times b times h.
- The enclosing triangle has area (1/2) times b times h, so the triangle to segment area ratio is 3 to 4 and the segment to bounding rectangle ratio is 2 to 3.
- The arc length is the length of the parabolic arc, computed from a closed form obtained by placing the vertex at the origin as y equals a times x squared and integrating.
- Length units match the input, and area is in those units squared.
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Parabolic Segment Area (Archimedes Theorem)