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RL Parallel Circuit Impedance Calculator

Find the total impedance, inductive reactance, phase angle, and branch current ratio of an RL parallel circuit from resistance R, inductance L, and frequency f.

Input

Enter the resistance, inductance, and frequency to compute the total impedance and phase angle of an RL parallel circuit.

Ω

Value of the resistor in the parallel branch (Ω)

H

Inductance of the coil in the parallel branch (H)

Hz

Frequency of the applied sinusoidal AC source (Hz)

Result

Total impedance |Z|

18.523355Ω

Real part 3.431147 Ω, imaginary part 18.2028 Ω

Inductive reactance XL

18.849556 Ω

Phase angle

79.325251 deg

Current ratio R to L

15.860014% to 84.139986%

Real ΩImag Ω18.523355 ΩPhase angle: 79.325251 deg

The total impedance and phase are derived from the sum of admittances 1/Z = 1/R + 1/(jωL), where ω is the angular frequency 2πf.

How it works

  • The total impedance follows from the sum of admittances 1/Z = 1/R + 1/(jωL), where the angular frequency is ω = 2πf.
  • The inductive reactance is XL = ωL = 2πfL in ohms.
  • The impedance magnitude is |Z| = 1 / sqrt((1/R)^2 + (1/XL)^2).
  • The phase angle is the phase of voltage relative to current and is positive for an inductive circuit.
  • In a parallel circuit each element shares the same voltage, so the current ratio is I_R to I_L equals (1/R) to (1/XL).

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